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GCSE Maths Number

Number

Number – Maths GCSE

Here we will learn about GCSE number, including place value, arithmetic, factors, multiples, primes and many other number topics.

There are also GCSE number worksheets based on Edexcel, AQA and OCR exam questions, along with further guidance on where to go next if you’re still stuck.

What is number?

Number is one of the topic areas of GCSE mathematics that features across all of the other areas of mathematics. You will need to be confident with all of the number topics to be able to solve problems involving algebra, ratio, geometry, statistics and probability.

You will also be asked questions that are purely number problems involving topics such as factors and multiples, prime numbers, indices, rounding or arithmetic.

In this page we will link to lots of other pages that will help with a variety of number topics. Let’s look at some of the different ways your number skills could be assessed in GCSE Mathematics.

What is number?

GCSE number worksheets

Over 75 GCSE number worksheets ready to download and give to your GCSE students. Each with functional and applied reasoning questions and exam style questions.

DOWNLOAD FREE

GCSE number worksheets

Over 75 GCSE number worksheets ready to download and give to your GCSE students. Each with functional and applied reasoning questions and exam style questions.

DOWNLOAD FREE

Place value

Place value is the value of each digit within a number.

A number is made up of digits. We need to be able to identify the location of each digit within the number as this can help to understand how large or small the number is.

To determine the value of a digit within a number we label each column with a title, like this,

For example,

Write down the value of the digit $5$ in the number $4.563.$

Locate the digit within the number.

4 \hspace{.2cm} . \hspace{.5cm} 5 \hspace{.5cm} 6 \hspace{.5cm} 3

⬆

2Recall the place value of that column.

The $5$ is in the tenths column.

3Write the value of the digit.

The value of the digit $5$ in the number $4.563$ is five tenths, or $0.5.$

Step-by-step guide: Place value

Arithmetic

Arithmetic is the study of numbers and the operations between them.

To use arithmetic with positive and negative numbers, we need to be able to calculate using the four main operations.

For example,

A group of young people are donating money to some charities. Altogether they collect $£5814$ which will be split equally between three charities. How much does each charity receive?

Determine which operator you need to use.

We need to divide $5814$ by $3.$

2Carry out the calculation.

Use a method of division such as short division.

Each charity receives $£1938.$

Step-by-step guide: Arithmetic

Rounding numbers

Rounding is when we approximate numbers in order to make them easier to deal with. We need to round down or up depending on which value is nearer. There are several ways we can be asked to round a number.

For example,

$1478.27$ can be rounded in several ways, including the below methods.

Step-by-step guide: Rounding numbers

Rounding to the nearest ones place, $\bf{10, \ 100}$ and $\bf{1000}$

$1478.47$ is $1500$ rounded to the nearest $100.$

Step-by-step guide: Rounding to the nearest 10, 100 and 1000

Rounding to decimal places

$1478.2735$ is $1478.3$ rounded to $1$ decimal place (the nearest tenth).

Step-by-step guide: Rounding decimals (coming soon)

Rounding to significant figures

$1478.47$ is rounded $1000$ to $1$ significant figure.

Step-by-step guide: Significant figures

Truncation is cutting a number off at a certain value with no need to round up.

Truncating a number is also linked with rounding.

$34.278$ is $34.2$ truncated to $1$ decimal place.

Step-by-step guide: Truncation

Estimation is using the approximated numbers for a calculation; we do not use the exact numbers.

Estimation is also linked with rounding.

$34.278$ is $34.3$ rounded to $1$ decimal place.

To estimate the answer to $367.1 \times 12.8$ we would calculate $400 \times 10$ to get an estimate of $4000.$

Step-by-step guide: Estimation

Upper and lower bounds

Upper and lower bounds are the maximum and minimum values that a number could have been before it was rounded. They can also be called limits of accuracy.

We need to be able to find upper and lower bounds of rounded numbers and use them in calculations. To do this we think about what the smallest and biggest numbers that round to a value for a given degree of accuracy are and then use the correct values for the calculation required.

We can display the upper and lower bounds using error intervals.

For example,

A number $x$ has been rounded to $1$ decimal place and given as $6.4.$

The smallest number that will round up to $6.4$ is $6.35$ and any number up to $6.45$ will round down to $6.4.$

Therefore we can write,

6.35 \leq x < 6.45.

We have to use $<$ for the upper bound as $6.45$ would round up to $6.5,$ not down to $6.4.$

However, any number up to $6.45$ would round down to $6.4$ (for example $6.44, \ 6.449, \ 6.44999999).$ This is why we write $6.45$ as the upper bound.

Step-by-step guide: Upper and lower bounds

Factors, multiples and primes

Factors, multiples and primes are different types of numbers.

In GCSE mathematics you may need to use factors, multiples and primes to solve problems. These may involve the following.

Step-by-step guide: Factors, multiples and primes

Factors

A factor is a number which divides into another number exactly with no remainders.

For example, the factors of $36$ are $1, 2, 3, 4, 6, 9, 12, 18$ and $36.$

Step-by-step guide: Factors

Multiples

A multiple of a number is a number in its times table.

For example, the first $5$ multiples of $13$ are $13, 26, 39, 52$ and $65.$

Step-by-step guide: Multiples

Primes

A prime number is a number that only has two factors, $1$ and itself.

For example, the first $10$ prime numbers are $2, 3, 5, 7, 11, 13, 17, 19, 23$ and $29.$

Step-by-step guide: Prime numbers

Prime factors

Prime factors are factors of a number that are also prime numbers.

For example, the prime factors of $60$ are $2, 3$ and $5.$

$60$ can be written as a product of its prime factors,

60=2\times 2\times 3\times 5.

Step-by-step guide: Prime factors

Lowest common multiple

The lowest common multiple (LCM) of two numbers is the lowest value that is a multiple of each number.

For example, the lowest common multiple of $12$ and $18$ is $36.$

Step-by-step guide: Lowest common multiple

Highest common factor

The highest common factor (HCF) of two numbers is the highest value that is a factor of each number.

For example, the highest common factor of $12$ and $18$ is $6.$

Step-by-step guide: Highest common factor

Negative numbers

Negative numbers are any numbers less than zero. They have a negative or minus sign $(-)$ in front of them. Numbers greater than zero are referred to as positive numbers. If there is no sign in front of a number the number is positive.

On the number line below we can see some positive and negative integers (whole numbers).

The numbers in orange are negative values and the blue numbers are positive values.

Zero is neither positive nor negative.

Just like you can add, subtract, multiply and divide positive numbers, you can do the same with negative numbers whether they are integers, decimals or fractions.

When adding and subtracting negative numbers we need to remember some rules.

If the signs are the same, replace them with a positive sign.

If the signs are different, replace them with a negative sign.

The chart below summarises this.

As a rule of thumb – same signs add, different signs subtract.

For example, $5-(-2)=5+2=7.$

When multiplying and dividing negative numbers we need to remember some rules.

If the signs are the same, the answer is positive.

If the signs are different, the answer is negative.

When multiplying negative numbers,

The same rules apply for dividing negative numbers.

For example, $5\times \left( -2 \right)=-10, \ \left( -45 \right)\div \left( -15 \right)=3.$

Step-by-step guide: Negative numbers

Fractions, decimals and percentages

Fractions, decimals and percentages are different ways of representing a proportion of the same amount. There is equivalence between fractions, decimals and percentages.

For example,

\frac{43}{100}=0.43=43\%

There are various methods of using fractions, decimals and percentages. They are important to understand as they are used in everyday life.

To succeed in GCSE mathematics you will need to be familiar with the following fraction, decimal and percentage topics,

Adding and subtracting fractions
Multiplying and dividing fractions
Equivalent fractions, improper fractions and mixed numbers
Ordering fractions
Fractions of an amount
Adding and subtracting decimals
Multiplying and dividing decimals
Percentage of an amount
Percentage multipliers
Percentage increase and decrease
Percentage change
Reverse percentages
Converting and comparing fractions, decimals and percentages

Step-by-step guide: Fractions, decimals and percentages

Fractions

Fractions are a way of writing equal parts of one whole.

There are two parts to a fraction, a numerator (top number) and a denominator (bottom number). The denominator shows how many equal parts the whole has been divided into. The numerator shows how many of the equal parts we have.

For example,

This shape has $9$ equal parts and $4$ of them are shaded.

This represents four ninths.

\frac{4}{9}

Numberfractions decimals and percentages image 1

Step-by-step guide: Fractions

Decimals

Decimals are a way of writing numbers that are not whole.

For example,

This shows the fraction $\frac{7}{10}.$

Numberfractions decimals and percentages image 2

$\frac{7}{10}$ can also be written as $\bf{0.7}$ .

Decimal numbers can be recognised as they have a decimal point.

A decimal place is a position after the decimal point.

For example,

$0.37$ has two decimal places.

There is a $3$ in the tenths place and $7$ in the hundredths place.

Step-by-step guide: Decimals

Percentages

Percentages are numbers which are expressed as parts of $100.$

Percent means “number of parts per hundred” and the symbol we use for this is the percent sign $\%.$

For example,

43\%.

There are $100$ equal parts and $43$ of them are shaded.

Numberfractions decimals and percentages image 3

Step-by-step guide: Percentages

Powers and roots

Power and roots are terms that express a repeated multiplication of a number.

Powers

For example,

We say this as $2$ to the power of $5$ because the number $2$ is being multiplied by itself $5$ times.

Roots

For example,

As $2 \times 2 \times 2 \times 2 \times 2=32,$ we can say that the $5th$ root of $32$ is $2.$

Step-by-step guide: Powers and roots

In GCSE mathematics you will need to be familiar with the following.

The powers of $\bf{0}$ and $\bf{1}$

For example,

6^{0} =1

4.8^{1}=4.8

Step-by-step guide: Power of 0

Negative powers

When a number is raised to a negative power, we calculate the positive reciprocal of that number.

For example,

10^{-2}=\frac{1}{10^{2}}=\frac{1}{100}

Step-by-step guide: Negative powers

Fractional powers

Fractional powers are a type of index that represents the nth root of a number.

For example,

8^{\frac{1}{3}}=\sqrt[3]{8}=2

Step-by-step guide: Fractional powers

Expressing a power with a different base

We can sometimes express a power with a different base in order to help to simplify expressions.

For example,

8 \times 2^{2}=2^{3} \times 2^{2}=2^{5}

Step-by-step guide: Expressing power with a different base (coming soon)

The laws of indices

Powers and roots are used in the five laws of indices,


Multiplying	To multiply two powers with the same base, add the indices.	$x^{a}\times{x^{b}}=x^{a+b}$
Dividing	To divide two powers with the same base, subtract the indices.	$x^{a}\div{x^{b}}=x^{a-b}$
Brackets	To raise one power to another power, multiply the indices.	$(x^{a})^{b}=x^{ab}$
Fractions	To raise a base to a fraction $\frac{m}{n},$ calculate the nth root of the base, raised to the power $m.$	$x^{\frac{m}{n}}=\sqrt[n]{x^m}$
Negatives	To raise a base to a negative number, take the positive power of the reciprocal.	$x^{-a}=\frac{1}{x^a}$

Step-by-step guide: Laws of indices

Standard form

Standard form is a way of writing very large or very small numbers by using powers of ten. It is also known as scientific notation.

Numbers in standard form are written in this format,

$a\times10^{n}$ .

Where $a$ is a number $1 \leq a < 10$ and $n$ is an integer.

To write a number in standard form we need to understand the place value of the number.

For example,

Let’s look at the number $8290000$ and write the digits in a place value table.

$10^6$	$10^5$	$10^4$	$10^3$	$10^2$	$10^1$	$10^0$
$8$	$2$	$9$	$0$	$0$	$0$	$0$

So, $8290000$ written in standard form is

$8.29\times10^{6}$ .

In GCSE mathematics you will be expected to convert between ordinary numbers and standard form as well as perform calculations with numbers in standard form with and without a calculator.

For example,

Calculate $(5\times10^{4}) \times (7\times10^{8})$ .

Write your answer in standard form.

Multiply the non-zero digits.

5 \times 7 = 35

2Multiply the powers of ten by adding the powers.

10^{4} \times 10^{8} = 10^{12}

3Put these two parts together and check whether the answer is in standard form.

35\times10^{12}

This number is not in standard form as $35$ is not between $1$ and $10.$

To convert $35$ to a decimal between $1$ and $10$ you need to divide it by $10.$ To maintain the value of the number, you need to multiply the power of ten by $10,$ which adds one to the exponent.

\hspace{1.3cm} 35 \times 10^{12}

\div \ 10 \ ↓ \hspace{2cm} \times \ 10 \ ↓

\hspace{1.3cm} 3.5\times10^{13}

Step-by-step guide: Standard form

Simple interest and compound interest

Simple and compound interest are two ways of calculating interest.

Simple interest is calculated on the original (principal) amount, whereas compound interest is calculated on the original amount and on the interest already accumulated on it.

The difference between simple and compound interest is that simple interest is calculated using only the original amount whereas compound interest works out the interest on a previous amount as well.

Check out the comparative example below to see the similarities and differences between the two forms of interest.

$\hspace{1.5cm} \bf{£100}$ is invested for $\bf{3}$ years at $\bf{2\%}$ per year. Find the final value.

Simple interest

$A=P(1+rt) \$

Here:

$P=100$
$r=0.02$ (as $2$ % = $0.02$ )
$t=3$

Substituting these values into the simple interest formula

$A=P(1+rt)$

We get:

$A = 100(1+0.02\times{3})\$

$A = 100(1+0.06)\$

$A = 100(1.06)\$

$A = 100\times{1.06}\$

$A = £106$

Compound interest

$A=P(1+\frac{r}{100})^{n} \$

Here:

$P=100$
$r=2$
$n=3$

Substituting these values into the compound interest formula

$A=P(1+\frac{r}{100})^{n} \$

We get:

$A = 100(1+(\frac{2}{100})^{3}$

$A = 100(1+0.02)^3\$

$A = 100(1.02)^3\$

$A = 100$ x $1.02^3\$

$A = £106.12$

As well as compound interest, you will also need to be able to work out compound depreciation. When the value of an asset reduces in price, it is known as depreciation.

Depreciation can be calculated the same way as compound interest but we must remember that the multiplier being used will be less than $1.$

For example,

A car worth $£20 \ 000$ depreciates by $10\%$ per year for $2$ years.

To find the value after $2$ years we calculate using the multiplier of $0.9.$

20 \ 000 \times 0.9^{2}=16 \ 200

The car will be worth $£16 \ 200.$

Step-by-step guide: Simple interest and compound interest

Types of numbers

Types of numbers are different sets of numerical values.

You should already be familiar with odd and even numbers, as well as positive and negative numbers, whole numbers (integers) and decimals.

You should also be familiar with other sets of numbers including square and cube numbers, prime numbers, and triangular numbers.

Below is a description of each of these types of numbers, along with a few examples.

Step-by-step guide: Types of numbers

Surds

Surds are a root that gives an irrational number. An irrational number can’t be written as a fraction, and in decimal form is infinitely long with no recurring pattern.

For example,

$\sqrt{5} \approx 2.23606 ,$ which is an irrational number.

The square root of $5$ is a surd.

In GCSE mathematics you need to be able to use surds in calculations without a calculator. You will need to be able to do the following.

You will also be expected to expand brackets involving surds and use surds in other algebra and geometry problems.

Step-by-step guide: Surds

Simplify surds

For example,

\begin{aligned} \sqrt{60} &=\sqrt{4 \times 15} \\\\ &=\sqrt{4} \times \sqrt{15} \\\\ &=2 \times \sqrt{15} \\\\ &=2 \sqrt{15} \end{aligned}

Step-by-step guide: Simplifying surds

Add and subtract surds

For example,

\begin{aligned} 2 \sqrt{5}+\sqrt{45} &=2 \sqrt{5}+3 \sqrt{5} \\\\ &=5 \sqrt{5} \end{aligned}

Step-by-step guide: Adding and subtracting surds

Multiply and divide surds

\begin{aligned} \frac{\sqrt{20}\times \sqrt{3}}{\sqrt{5}} & =\frac{\sqrt{60}}{\sqrt{5}} \\\\ & =\frac{2\sqrt{15}}{\sqrt{5}} \\\\ & =2\sqrt{3} \end{aligned}

Step-by-step guide: Multiplying and dividing surds

Rationalise denominators

For example,

\frac{2}{\sqrt{5}}=\frac{2\sqrt{5}}{5}

Step-by-step guide: Rationalise the denominator

Money problems

Money problems are types of questions that involve finance. Examples could include,

Best buys
Using exchange rates
Budgeting for a holiday
Calculating the amount spent on a shopping trip

To be able to solve money problems in GCSE mathematics you will need to be confident with decimal arithmetic and rounding.

When calculating with money it will be important to leave answers to two decimal places if the answer is in pounds, $£.$

For example,

A pack of $6$ rolls of toilet paper costs $£2.45.$ A pack of $9$ toilet rolls costs $£3.59.$

How much is the cheapest price for $36$ toilet rolls?

We need to multiply the cost of $6$ rolls by $6$ and multiply the cost of $9$ rolls by $4.$

£2.45\times 6 = £14.70

£3.59\times 4 = £14.36

The cheapest price for $36$ rolls of toilet paper is $£14.36.$

Step-by-step guide: Money problems maths

Calculator skills

Calculator skills are important for the GCSE mathematics calculator papers and will help you later in life in many careers.

You may be asked to perform calculations involving powers and roots, fractions and trigonometric functions.

For example,

Work out $\frac{\sqrt[3]{340}-{{2.6}^{5}}}{\sin 25{}^\circ },$ write down all the numbers on your calculator display.

= -264.6223272

Step-by-step guide: Calculator skills

Common misconceptions

Sometimes we need a zero in as a place holder when rounding with decimal numbers

Round $3.4973$ to $2$ decimal places will be $3.50.$ We need the zero in the hundredths column. So, $3.4 \colorbox{yellow}{9}73 \approx 3.50$ we round up.

Upper bound is incorrect

It is very common for students to put an incorrect upper bound.

For example, if a length has been rounded to $56 \ cm$ to the nearest $cm,$ they may write the upper bound as $56.4 \ cm.$ The upper bound must be bigger than $56.4 \ cm$ as $56.49$ also rounds down to $56,$ so does $56.499999999….$ The upper bound in this case is $56.5 \ cm.$

$\bf{1}$ and prime numbers

$1$ is not a prime number. This is because it only has one factor, rather than the $2$ factors needed to be a prime number.

Factors and multiples

Factors and multiples are easily mixed up. Remember multiples are the multiplication table, whereas factors are the numbers that go into another number without a remainder.

Raising a negative number to a power greater than one

Remember when raising a negative number to a power greater than $1$ the resulting answer could be positive or negative. When you raise a negative number to an odd exponent the resulting answer is negative, when you raise a negative number to an even exponent the resulting answer is positive.

Raising a number to a negative power

A common error is thinking that raising a number to a negative power makes the answer negative.

For example, the value of $3^{-2}$ is sometimes incorrectly given as $-9.$

The correct answer is $\frac{1}{9}$ as the negative power gives the reciprocal to the base number.

Practice number questions

0.03

0.3

0.037

0.036

We are rounding to $2$ significant figures. The first significant figure is $3.$ The $5$ in the ten thousandths column indicates we round the $6$ up.

Upper bound $= 42.9 \ cm, \$ lower bound $= 42.7 \ cm$

Upper bound $= 42.94 \ cm,$ lower bound $= 42.75 \ cm$

Upper bound $= 42.8 \ cm, \$ lower bound $= 42.9 \ cm$

Upper bound $= 42 \ cm, \$ lower bound $= 43 \ cm$

The error interval of the height, $h,$ is $21.35 \ cm \leq h < 21.45 \ cm.$

By adding the lower bounds for the height, we find the lower bound for the combined height.

By adding the upper bounds for the height, we find the upper bound for the combined height.

20

2

80

40

Write down the multiples of $8$ and the multiples of $10$ and see which is the lowest number that occurs in both lists.

Multiples of $8$ : $8, 16, 24, 32, 40, 48, …$

Multiples of $10$ : $10, 20, 30, 40, 50, …$

So, $40$ is the LCM of $8$ and $10.$

Alternatively you can use prime factorisation and Venn diagrams.

Number practice question 3

\text{LCM}=2\times 2\times 2\times 5=40

800

858

338

700

Number practice question 4

3

1

4.5

9

\sqrt[4]{81}\div 9^{\frac{1}{2}}=3\div{3}=1

12+2\sqrt{7}

12+4\sqrt{28}

12+4\sqrt{7}

12+8\sqrt{7}

Simplify $\sqrt{28}=\sqrt{4 \times 7}=2 \sqrt{7}.$

\begin{aligned} &4 \times 3=12 \\\\ &4 \times 2 \sqrt{7}=8 \sqrt{7} \end{aligned}

So the final answer is $12+8\sqrt{7}.$

GCSE number questions

1. Work out an estimate for $\frac{67.3 \times 21.6}{0.46}.$

(3 marks)

Show answer

Rounding one original number to $1$ significant figure $70$ or $20$ or $0.5.$

(1)

Calculation involving all three rounded numbers.

(1)

2800

(1)

2. (a) Find the highest common factor of $36$ and $84.$

(b) Two buses leave the depot at $12.00.$

Bus A takes $40$ minutes to complete its journey and return to the depot.

Bus B takes $25$ minutes to complete its journey and return to the depot.

What time is it when both buses are back at the depot together?

(5 marks)

Show answer

(a)

List of factors or prime factor decomposition of one or both.

(1)

HCF of $12$ .

(1)

(b)

Prime factorisation or list of multiples of one or both.

(1)

LCM of $200$ minutes.

(1)

$15.20$ or $3.20 \ pm$

(1)

3. (a) Expand and simplify $(3+\sqrt{7})(3-\sqrt{7}).$

(b) Hence, or otherwise, show that $\frac{16}{3+\sqrt{7}}$ can be written as $24-8\sqrt{7}.$

(5 marks)

Show answer

(a)

Any two correct terms, $9+3\sqrt{7}-3\sqrt{7}-7$ .

(1)

All four correct terms, $9+3\sqrt{7}-3\sqrt{7}-7$ .

(1)

Simplified to $2$ .

(1)

(b)

\frac{16(3-\sqrt{7})}{(3+\sqrt{7})(3-\sqrt{7})}

(1)

$\frac{48-16\sqrt{7}}{2}$ leading to $24-8\sqrt{7}$ as required

(1)

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